实现makeStrings函数：生成判断能否观看《黑客帝国》的字符串数组

需求说明 #

• 接收一个包含name（姓名）和age（年龄）属性的对象数组作为参数
• 返回对应规则的字符串数组：
  • 若对象的age ≥ 18，生成字符串：[姓名] can go to The Matrix
  • 若对象的age < 18，生成字符串：[姓名] is under age!!

修正后的实现代码 #

function makeStrings(people) {
  return people.map(person => {
    return person.age >= 18 
      ? `${person.name} can go to The Matrix` 
      : `${person.name} is under age!!`;
  });
}

测试验证 #

测试代码 #

console.log(makeStrings([
    {name: "Angelina Jolie", age: 80},
    {name: "Eric Jones", age: 2},
    {name: "Paris Hilton", age: 5},
    {name: "Kayne West", age: 16},
    {name: "Bob Ziroll", age: 100}
]));

预期输出 #

["Angelina Jolie can go to The Matrix", "Eric Jones is under age!!", "Paris Hilton is under age!!", "Kayne West is under age!!", "Bob Ziroll can go to The Matrix"]

内容的提问来源于stack exchange，提问作者GardenDarts