批处理脚本中For循环仅输出单个nslookup IPv4结果的问题

我在批处理脚本中使用nslookup.exe查询输入域名的所有可用IPv4地址，但即使存在多个地址，脚本也仅输出其中一个。直接在cmd.exe中执行nslookup能显示所有地址，但脚本的for循环解析逻辑存在问题，无法捕获全部结果。

问题现象 #

输入amazon.com或microsoft.com时，脚本输出仅包含单个IPv4地址：

Domain Name: amazon.com
IPv4 Address: 205.251.242.103

Domain Name: microsoft.com
IPv4 Address: 20.112.250.133

而直接在cmd中执行nslookup能返回全部地址（含IPv4和IPv6）：

执行nslookup amazon.com的输出：

C:\Users>nslookup amazon.com
Server:  xxxxxxxxx
Address:  xxx.xx.xxx.xx

Non-authoritative answer:
Name:    amazon.com
Addresses:  54.239.28.85
          52.94.236.248
          205.251.242.103

执行nslookup microsoft.com的输出：

C:\Users>nslookup microsoft.com
Server:  xxxxxxxxx
Address:  xxx.xx.xxx.xx

Non-authoritative answer:
Name:    microsoft.com
Addresses:  2603:1030:c02:8::14
          2603:1020:201:10::10f
          2603:1010:3:3::5b
          2603:1030:b:3::152
          2603:1030:20e:3::23c
          20.231.239.246
          20.76.201.171
          20.70.246.20
          20.236.44.162
          20.112.250.133

尝试过的脚本及问题 #

方案1：用findstr过滤Address行 #

for /f "tokens=2" %%b in ('nslookup -type=A !domain_name! 2^>nul ^| findstr /C:"Address"') do (
    if not "%%b"=="" (  
        echo Domain Name: !domain_name!
        echo IPv4 Address: %%b
    ) else (
        echo I encountered an error while looking up the domain name, or no Address records were found.
    )
)

问题：仅输出单个IPv4地址，无法捕获Addresses:后的多行结果。

方案2：移除findstr，用delims分割 #

for /f "tokens=2 delims=:" %%b in ('nslookup -type=A !domain_name! 2^>nul') do (
  if not "%%b"=="" (
    echo Domain Name: !domain_name!
    echo IPv4 Address: %%b
  )
)

if defined b (
  rem something was found
) else (
  echo No IPv4 addresses found
)

问题：错误将UnKnown当作IPv4地址输出：

Domain Name: microsoft.com
IPv4 Address:  UnKnown
Domain Name: microsoft.com
IPv4 Address:  20.231.239.246

方案3：结合delims和findstr，收集地址到变量 #

set "ipv4_addresses="
for /f "tokens=2 delims=: " %%b in ('nslookup -type=A !domain_name! 2^>nul ^| findstr /R /C:"Address"') do (
  echo Domain Name: !domain_name!
  echo IPv4 Address: %%b
  set "ipv4_addresses=!ipv4_addresses! %%b"
)

rem If no IPv4 addresses are found, display a message
if not defined ipv4_addresses echo No IPv4 addresses were found for !domain_name!

问题：仍仅输出单个IPv4地址。

修复后的脚本 #

问题根源在于nslookup多地址行仅以Addresses:开头，后续地址无Address关键字，之前的findstr过滤掉了这些行；同时需区分IPv4和IPv6地址，避免混入无关结果。

修复后的脚本：

@echo off
setlocal enabledelayedexpansion

set "domain_name=%~1"
if not defined domain_name (
    echo Usage: %0 ^<domain_name^>
    exit /b 1
)

echo Domain Name: !domain_name!
echo IPv4 Addresses:
set "found=0"

for /f "skip=4 tokens=*" %%a in ('nslookup -type=A !domain_name! 2^>nul') do (
    rem 匹配纯IPv4格式的行，过滤无关内容
    echo "%%a" | findstr /R "^[0-9][0-9]*\.[0-9][0-9]*\.[0-9][0-9]*\.[0-9][0-9]*$" >nul
    if not errorlevel 1 (
        echo - %%a
        set "found=1"
    )
)

if !found! equ 0 (
    echo No IPv4 addresses found for !domain_name!
)

endlocal

脚本说明 #

• skip=4：跳过nslookup输出的前4行服务器信息，直接处理结果部分
• findstr正则匹配：仅保留纯IPv4格式的行，过滤掉Addresses:、IPv6及空行
• enabledelayedexpansion：确保循环内变量正常更新

测试输出示例：

Domain Name: amazon.com
IPv4 Addresses:
- 54.239.28.85
- 52.94.236.248
- 205.251.242.103

内容的提问来源于stack exchange，提问作者Nelie