如何移除复杂对象中指定键值为null的子对象？

核心逻辑是对issues数组执行筛选操作，保留fields.customfield_12000不为null的对象，以下是具体实现示例：

JavaScript 实现 #

// 原始输入数据
const payload = {
   "issues":[
      {
         "key":"13996",
         "fields":{
            "customfield_13100":null,
            "customfield_15400":null,
            "customfield_13102":null,
            "customfield_13104":null,
            "customfield_12809":"",
            "lastViewed":null,
            "customfield_12000":[
               "870CA25F"
            ]
         }
      },
      {
         "key":"13996",
         "fields":{
            "customfield_13100":null,
            "customfield_15400":null,
            "customfield_13102":null,
            "customfield_13104":null,
            "customfield_12809":"",
            "lastViewed":null,
            "customfield_12000":null
         }
      },
      {
         "key":"13996",
         "fields":{
            "customfield_13100":null,
            "customfield_15400":null,
            "customfield_13102":null,
            "customfield_13104":null,
            "customfield_12809":"",
            "lastViewed":null,
            "customfield_12000":[
               "870CA25F"
            ]
         }
      }
   ]
};

// 执行过滤
const filteredPayload = {
  issues: payload.issues.filter(issue => issue.fields.customfield_12000 !== null)
};

// 输出结果
console.log(JSON.stringify(filteredPayload, null, 2));

Python 实现 #

import json

# 原始输入数据
payload_json = '''
{
   "issues":[
      {
         "key":"13996",
         "fields":{
            "customfield_13100":null,
            "customfield_15400":null,
            "customfield_13102":null,
            "customfield_13104":null,
            "customfield_12809":"",
            "lastViewed":null,
            "customfield_12000":[
               "870CA25F"
            ]
         }
      },
      {
         "key":"13996",
         "fields":{
            "customfield_13100":null,
            "customfield_15400":null,
            "customfield_13102":null,
            "customfield_13104":null,
            "customfield_12809":"",
            "lastViewed":null,
            "customfield_12000":null
         }
      },
      {
         "key":"13996",
         "fields":{
            "customfield_13100":null,
            "customfield_15400":null,
            "customfield_13102":null,
            "customfield_13104":null,
            "customfield_12809":"",
            "lastViewed":null,
            "customfield_12000":[
               "870CA25F"
            ]
         }
      }
   ]
}
'''

payload = json.loads(payload_json)
# 执行过滤
filtered_payload = {
    "issues": [issue for issue in payload["issues"] if issue["fields"]["customfield_12000"] is not None]
}

# 输出结果
print(json.dumps(filtered_payload, indent=2))

关键说明 #

• 你之前尝试的filterObject是针对对象键值对的过滤方法，但这里需要的是对数组元素的筛选，因此要使用数组级别的过滤API（比如JS的Array.filter、Python的列表推导式）
• 筛选条件直接判断目标字段是否不为null，符合条件的元素会被保留，不符合的则被移除
• 最终将筛选后的数组重新包装为原数据结构，即可得到预期输出

内容的提问来源于stack exchange，提问作者muledev