基于Jolt实现根据city字段值动态设置address字段的技术需求

源JSON #

注：原JSON存在语法错误，已修正"age"字段的冒号缺失问题

{
  "name": "test",
  "age": 10,
  "city": null,
  "pinCode": "400081",
  "address": {
    "buildingNo": "B-301"
  }
}

转换需求 #

• 当city字段值为null时，结果中person.address需设置为null，输出示例：

{
  "person": {
    "name": "test",
    "age": 10,
    "address": null
  }
}

• 当city字段值不为null时，person.address需包含pinCode和原address.buildingNo字段，输出示例：

{
  "person": {
    "name": "test",
    "age": 10,
    "address": {
      "pinCode": "400081",
      "buildingNo": "B-301"
    }
  }
}

尝试的Jolt规则（未达到预期） #

[
  {
    "operation": "shift",
    "spec": {
      "name": "person.name",
      "age": "person.age",
      "city": {
        "null": {
          "@(1,person.address)": null
        },
        "*": {
          "@1": "person.address.city"
        }
      },
      "pinCode": "person.address.pinCode",
      "address": {
        "buildingNo": "person.address.buildingNo"
      }
    }
  }
]

[
  {
    "operation": "shift",
    "spec": {
      "name": "person.name",
      "age": "person.age",
      "pinCode": "temp.pinCode",
      "address": {
        "buildingNo": "temp.buildingNo"
      },
      "city": "city"
    }
  },
  {
    "operation": "shift",
    "spec": {
      "person": "person",
      "city": {
        "null": {
          "#null": "person.address"
        },
        "*": {
          "@2,temp": "person.address"
        }
      }
    }
  },
  {
    "operation": "remove",
    "spec": {
      "city": "",
      "temp": ""
    }
  }
]

配置说明 #

1. 第一个shift操作：提取公共字段name、age到person下，同时将pinCode和buildingNo暂存到temp对象，保留city字段用于后续判断。
2. 第二个shift操作：根据city的值进行分支处理：
   • 若city为null，直接将person.address设为null；
   • 若city不为null，将暂存的temp对象内容赋值给person.address。
3. 第三个remove操作：清理临时字段city和temp，得到最终结构。

内容的提问来源于stack exchange，提问作者Ajinkya