使用YAML部署Azure Function至FunctionApp槽时Zip文件找不到问题

使用C#开发Azure Function，通过流水线实现构建→测试→发布代码→用Bicep搭建各环境基础设施→将发布的Function代码部署到对应Function App的流程，但部署时出现Zip文件找不到的错误：

##[error]Error: No package found with specified pattern: /home/vsts/work/1/a/*.zip

日志显示发布的Zip文件在/home/vsts/work/1/s目录下，但部署任务在/1/a目录查找。以下是发布和部署阶段的YAML配置：

发布阶段YAML #

- task: DotNetCoreCLI@2
  displayName: "dotnet publish"
  inputs:
    command: publish
    arguments: '--configuration Release --output publish_output'
    projects: 'src/**/*.csproj'
    publishWebProjects: false
    modifyOutputPath: false
    zipAfterPublish: false
- task: ArchiveFiles@2
  displayName: "Archive files (into zip)"
  inputs:
    rootFolderOrFile: "$(System.DefaultWorkingDirectory)/publish_output"
    includeRootFolder: false
    archiveFile: "$(System.DefaultWorkingDirectory)/build$(Build.BuildId).zip"
- task: PublishBuildArtifacts@1
  displayName: "Publish build artifacts"
  inputs:
    PathtoPublish: '$(System.DefaultWorkingDirectory)/build$(Build.BuildId).zip'

部署阶段YAML #

- task: AzureFunctionApp@1 # Add this at the end of your file
  displayName: 'Deploy Function code to FunctionApp Slot'
  inputs:    
    azureSubscription: 'ServiceConnection'
    appType: functionAppLinux # default is functionApp
    appName: 'f2404dev-app'
    package: '$(System.ArtifactsDirectory)/**/*.zip'

问题核心是发布构件的配置不完整，以及部署阶段未正确处理构件的下载路径：

1. 发布构件时需明确指定构件名称
   PublishBuildArtifacts@1任务默认会将构件发布到名为drop的集合中，若不指定artifactName，后续部署阶段查找时容易出现路径匹配问题。修改发布阶段的PublishBuildArtifacts@1任务，添加明确的构件名称：

   - task: PublishBuildArtifacts@1
     displayName: "Publish build artifacts"
     inputs:
       PathtoPublish: '$(System.DefaultWorkingDirectory)/build$(Build.BuildId).zip'
       artifactName: 'function-build' # 指定唯一构件名称，避免混淆
   

2. 部署阶段需先下载构件再引用
   若发布阶段和部署阶段不在同一个作业（Job）中，必须先添加下载构件的任务，将发布的Zip包拉取到部署作业的本地目录。修改部署阶段的配置：

   - task: DownloadBuildArtifacts@0
     displayName: 'Download build artifacts'
     inputs:
       buildType: 'current'
       downloadType: 'single'
       artifactName: 'function-build' # 和发布阶段指定的名称一致
       downloadPath: '$(System.ArtifactsDirectory)'
   - task: AzureFunctionApp@1
     displayName: 'Deploy Function code to FunctionApp Slot'
     inputs:    
       azureSubscription: 'ServiceConnection'
       appType: functionAppLinux
       appName: 'f2404dev-app'
       package: '$(System.ArtifactsDirectory)/function-build/**/*.zip' # 精确指向下载后的Zip包路径
   

3. 可选：简化Zip包生成流程
   可以直接利用DotNetCoreCLI@2的内置功能生成Zip包，省去ArchiveFiles@2的步骤，减少出错点：

   - task: DotNetCoreCLI@2
     displayName: "dotnet publish and zip"
     inputs:
       command: publish
       arguments: '--configuration Release --output publish_output'
       projects: 'src/**/*.csproj'
       publishWebProjects: false
       modifyOutputPath: false
       zipAfterPublish: true # 自动生成Zip包
   - task: PublishBuildArtifacts@1
     displayName: "Publish build artifacts"
     inputs:
       PathtoPublish: '$(System.DefaultWorkingDirectory)/publish_output/*.zip' # 直接引用自动生成的Zip包
       artifactName: 'function-build'
   

内容的提问来源于stack exchange，提问作者Anders Juul