如何在Kong Ingress 3.1.x中修改上游超时？配置遇解码错误

在Kong Ingress 2.7.x版本中，我通过upstream-timeout插件配置上游超时，配置如下：

apiVersion: configuration.konghq.com/v1
kind: KongPlugin
metadata:
  name: up-timeout
  annotations:
    kubernetes.io/ingress.class: kong
  labels:
    global: "true"
plugin: upstream-timeout
config:
  connect_timeout: 30000
  send_timeout: 3600000
  read_timeout: 3600000

升级至3.1.x后，尝试在Service的YAML中通过注解配置超时：

apiVersion: v1
kind: Service
metadata:
  name: logistics-simulator
  annotations:
    konghq.com/override: kong-timeout
    konghq.com/connect-timeout: 3600000
spec:
    type: ClusterIP
    ports:
    - port: 80 
    selector:
        app: logistics-simulator

但在AKS环境中遇到解码错误：

error: unable to decode "/home/vsts/work/_temp/Service_logistics-simulator_1712325946614": json: cannot unmarshal number into Go struct field ObjectMeta.metadata.annotations of type string
##[error]error: unable to decode "/home/vsts/work/_temp/Service_logistics-simulator_1712325946614": json: cannot unmarshal number into Go struct field ObjectMeta.metadata.annotations of type string

请问该如何正确配置Kong Ingress 3.1.x的上游超时？

方式一：修正Service注解格式 #

Kubernetes的注解值必须为字符串类型，你当前配置的3600000是数字类型，导致解码失败。只需把超时值用引号包裹转为字符串即可：

apiVersion: v1
kind: Service
metadata:
  name: logistics-simulator
  annotations:
    konghq.com/override: kong-timeout
    konghq.com/connect-timeout: "3600000"  # 转为字符串格式
    konghq.com/send-timeout: "3600000"     # 按需添加发送超时
    konghq.com/read-timeout: "3600000"     # 按需添加读取超时
spec:
    type: ClusterIP
    ports:
    - port: 80 
    selector:
        app: logistics-simulator

方式二：继续使用KongPlugin配置（兼容旧版本） #

Kong Ingress 3.1.x依然支持upstream-timeout插件的配置方式，如果你习惯原有逻辑，可继续使用该方案：

apiVersion: configuration.konghq.com/v1
kind: KongPlugin
metadata:
  name: up-timeout
  annotations:
    kubernetes.io/ingress.class: kong
  labels:
    global: "true"  # 全局生效，若需局部绑定可移除该标签
plugin: upstream-timeout
config:
  connect_timeout: 30000
  send_timeout: 3600000
  read_timeout: 3600000

若不需要全局生效，可在目标Service或Ingress中添加注解konghq.com/plugins: up-timeout，实现插件的局部绑定。

内容的提问来源于stack exchange，提问作者whebz