Java中如何根据指定RuleID过滤List排除对应RuleDesc

需要实现过滤逻辑：当RuleType对象的ruleID属于指定排除集合（ruleIdsToExclude = "Type1,Type2,Type3,Type4"）时，排除该对象的RuleDesc。现有测试数据如下：

rulesList              ArrayList
  [0]                  RuleType
     ruleDescr         “test1”
     ruleID            “Rule1”
  [1]                  Ruletype
     ruleDescr         “test2”
     ruleID            “Type2”
  [2]                  RuleType
     ruleDescr        "test3"
     ruleID           "Type3"
  [3]                  RuleType
     ruleDescr        "test4"
     ruleID           "Rule4"

过滤后最终列表应仅保留test1和test4，以下是修改后的Java代码实现：

private List<String> extractAlertsInfoList(RulesListType thisDetailRulesList) {
    List<String> alertsInfoList = new ArrayList<>();
    if (thisDetailRulesList != null && CollectionUtils.isNotEmpty(thisDetailRulesList.getRule())) {
        List<RuleType> rulesList = thisDetailRulesList.getRule();
        // 初始化排除ID集合，转为HashSet提升查询效率
        Set<String> excludedRuleIds = new HashSet<>(Arrays.asList("Type1,Type2,Type3,Type4".split(",")));

        for (RuleType thisRule : rulesList) {
            String ruleId = thisRule.getRuleID().toString().trim();
            String ruleDesc = thisRule.getRuleDesc();
            // 仅保留描述有效且ID不在排除列表中的项
            if (isValidRuleDescription(ruleDesc) && !excludedRuleIds.contains(ruleId)) {
                alertsInfoList.add(ruleDesc);
            }
        }
    }
    return alertsInfoList;
}

private boolean isValidRuleDescription(String ruleDesc) {        
    return ruleDesc != null && !ruleDesc.isEmpty();
}

• 将排除ID字符串转为HashSet：避免循环内重复分割字符串，同时HashSet的contains方法查询效率远高于List，优化性能
• 新增排除判断：在原有描述有效性判断的基础上，增加!excludedRuleIds.contains(ruleId)，确保不在排除集合中的规则才会被加入结果列表
• 提前获取ruleDesc：减少重复调用getRuleDesc()的次数，提升代码简洁性

内容的提问来源于stack exchange，提问作者samd