Laravel中是否存在替代PHP原生in_array函数的等效方法？

Hey there! I totally get where you're coming from—switching to Laravel's helper methods can feel a bit tricky when you're used to native PHP functions. Let's clear this up:

First, the reason Str::contains didn't work for you is that it's designed for string operations, not arrays. It checks if a string contains a given substring (or any substring from an array), which is a completely different use case than in_array.

Luckily, Laravel has two great alternatives for in_array:

1. Arr::contains (数组助手类) #

This is the closest direct replacement for in_array since it works directly with native PHP arrays. It even supports strict type checking just like in_array's third parameter.

Examples:

• 基础检查：

  use Illuminate\Support\Arr;
  
  Arr::contains(['apple', 'banana', 'cherry'], 'banana'); // 返回 true
  

• 严格类型检查（对应in_array($needle, $haystack, true)）：

  Arr::contains([1, 2, 3], '1', true); // 返回 false（因为'1'是字符串，不是整数）
  

2. Collection 的 contains() 方法 #

如果你在处理集合（这在Laravel中非常常见），可以直接使用集合内置的contains()方法。先把数组转成集合，再调用方法即可：

Examples:

• 基础值检查：

  collect(['apple', 'banana', 'cherry'])->contains('banana'); // 返回 true
  

• 检查关联数组的键值对：

  collect([
      ['name' => 'John', 'age' => 30],
      ['name' => 'Jane', 'age' => 25]
  ])->contains('name', 'Jane'); // 返回 true
  

• 用回调做复杂检查：

  collect([1, 2, 3, 4])->contains(function ($value, $key) {
      return $value > 2;
  }); // 返回 true
  

两种方法都很实用——如果处理原生数组就用Arr::contains，如果已经在使用Laravel集合做链式操作，就选集合的contains()。

内容的提问来源于stack exchange，提问作者Petro Gromovo