如何将Python正则提取的代理地址与对应时间记录配对组合为指定格式

The issue with your current code is that it yields all proxy addresses first, then all time records—so they’re output as two separate groups instead of paired one-to-one. To fix this, we can collect both sets of data into lists first, then combine them by zipping the lists together. Here’s how to adjust your code:

import re

def tst():
    text = ''' <script> '''  # Your original HTML text here
    proxies = []
    timestamps = []
    
    # Collect proxy addresses
    if proxy_matches := re.findall(r"(?:<td\s[^>]*?><font\sclass=spy14>(.*?)<script.*?\\"\+(.*?)</script)", text):
        for proxy, port in proxy_matches:
            proxies.append(f"{proxy}:{''.join(port)}")
    
    # Collect time records
    if time_matches := re.findall(r"<td colspan=1><font class=spy1><font class=spy14>(.*?)</font> (\d+[:]\d+) <font class=spy5>([(]\d+ \w+ \w+[)])", text):
        for date, time, taken in time_matches:
            timestamps.append(f"{date} {' '.join([time, taken])}")
    
    # Pair and yield combined entries
    for proxy, timestamp in zip(proxies, timestamps):
        yield f"{proxy} - {timestamp}"

for entry in tst():
    print(entry)

Key Changes: #

1. Collect Data into Lists: Instead of yielding each proxy/time immediately, we store them in proxies and timestamps lists.
2. Zip and Combine: Using zip(proxies, timestamps) pairs each proxy with the corresponding time record (assuming the number of proxies and times are equal, which they are in your example).
3. Yield Paired Strings: We generate the combined format you want directly in the final loop.

Expected Output: #

51.155.10.0:8000 - 27-oct-2022 11:05 (49 mins ago)
178.128.96.80:7497 - 27-oct-2022 11:04 (50 mins ago)
98.162.96.41:4145 - 27-oct-2022 11:03 (51 mins ago)

This approach keeps your existing regex logic intact while ensuring the data is paired correctly. If you ever encounter a mismatch in the number of proxies and times, you could add a check (like using itertools.zip_longest to handle missing entries), but this should work perfectly for your current use case.

内容的提问来源于stack exchange，提问作者xnoob