Eigen::Tensor链式操作后调用.sum()无法提取标量的编译错误求助
Eigen Tensor库sum()无法提取标量的编译错误解决方法
问题代码
#include <iostream> #include <unsupported/Eigen/CXX11/Tensor> int main() { using namespace Eigen; // 填充张量数据 Tensor<std::complex<double>, 4> xi1st(3, 3, 3, 3); for (int i = 0; i < 3; ++i) { for (int j = 0; j < 3; ++j) { for (int k = 0; k < 3; ++k) { for (int l = 0; l < 3; ++l) { xi1st(i, j, k, l) = std::complex<double>(i + j + k + l, i - j + k - l); } } } } // 示例索引 int i = 1, j = 1, k = 1; // 尝试从嵌套操作中提取求和结果 auto xi1st_slice = xi1st.slice(Eigen::array<Index, 4>({0, i, j, k}), Eigen::array<Index, 4>({3, 1, 1, 1})); auto xi1st_conj = xi1st_slice.conjugate(); std::complex<double> xi1st_sum = xi1st_conj.sum(); std::cout << "xi1st_sum: " << xi1st_sum << std::endl; return 0; }
编译错误信息
<source>: In function 'int main()': <source>:31:52: error: conversion from 'const Eigen::TensorReductionOp<Eigen::internal::SumReducer<std::complex<double> >, const Eigen::DimensionList<long int, 4>, const Eigen::TensorCwiseUnaryOp<Eigen::internal::scalar_conjugate_op<std::complex<double> >, const Eigen::TensorSlicingOp<const std::array<long int, 4>, const std::array<long int, 4>, Eigen::Tensor<std::complex<double>, 4> > >, Eigen::MakePointer>' to non-scalar type 'std::complex<double>' requested 31 | std::complex<double> xi1st_sum = xi1st_conj.sum(); | ~~~~~~~~~~~~~~^~ Compiler returned: 1
问题原因与解决方法
Eigen的Tensor模块采用**延迟求值(lazy evaluation)**机制,slice、conjugate、sum这类操作不会立即计算结果,而是返回一个代表运算逻辑的表达式对象。sum()返回的TensorReductionOp本质是一个0维张量表达式,无法直接隐式转换为std::complex<double>,必须显式触发求值并提取标量。
两种可行的解决方式:
调用
()运算符直接提取0维张量的唯一元素:
修改求和赋值行:std::complex<double> xi1st_sum = xi1st_conj.sum()();链式调用写法:
std::complex<double> xi1st_sum = xi1st .slice(Eigen::array<Index, 4>({0, i, j, k}), Eigen::array<Index, 4>({3, 1, 1, 1})) .conjugate() .sum()();使用
eval()显式触发求值:eval()会先计算出完整的0维张量对象,该对象可隐式转换为对应标量类型:std::complex<double> xi1st_sum = xi1st_conj.sum().eval();链式调用写法:
std::complex<double> xi1st_sum = xi1st .slice(Eigen::array<Index, 4>({0, i, j, k}), Eigen::array<Index, 4>({3, 1, 1, 1})) .conjugate() .sum() .eval();
两种方法都能正确获取求和后的标量值,解决编译错误。
内容的提问来源于stack exchange,提问作者Yes
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