PowerShell中如何静态初始化哈希表嵌套结构？

错误代码 #

$table = @{"a" = @{"x" = 1, "y" = 2, "z" = 3}, "b" = @{"x" = 3, "y" = 4, "z" = 6}}

错误信息 #

PS C:\Users\nkannapp> $table = @{"a"=@{"x" = 1, "y" = 2, "z" = 3}, "b"=@{"x" = 3, "y" = 4, "z" = 6}}
At line:1 char:16

• $table = @{"a"=@{"x" = 1, "y" = 2, "z" = 3}, "b"=@{"x" = 3, "y" = 4, ...

• ~~~~~~~~~~~~~~~~~~~~~~~~~~~~
  

The assignment expression is not valid. The input to an assignment operator must be an object that is able to accept
assignments, such as a variable or a property.
At line:1 char:46

• $table = @{"a"=@{"x" = 1, "y" = 2, "z" = 3}, "b"=@{"x" = 3, "y" = 4, ...

• ~~~
  

The assignment expression is not valid. The input to an assignment operator must be an object that is able to accept
assignments, such as a variable or a property.

修复后的正确代码 #

紧凑写法 #

$table = @{"a" = @{"x" = 1; "y" = 2; "z" = 3}; "b" = @{"x" = 3; "y" = 4; "z" = 6}}

换行格式化（可读性更强） #

$table = @{
    "a" = @{
        "x" = 1
        "y" = 2
        "z" = 3
    }
    "b" = @{
        "x" = 3
        "y" = 4
        "z" = 6
    }
}

错误原因 #

PowerShell初始化哈希表时，键值对之间必须用分号（;）分隔，逗号（,）是PowerShell的数组创建运算符。原代码中的逗号会被解析为将多个对象打包成数组，破坏了哈希表的结构定义，最终触发赋值表达式无效的报错。

内容的提问来源于stack exchange，提问作者Neelakantan K