树莓派4上Adafruit指纹传感器库AttributeError报错求助
问题描述
测试Adafruit指纹传感器时,设备已被终端识别,但运行测试代码出现以下错误:
Traceback (most recent call last):
File "", line 9, in
AttributeError: module 'adafruit_fingerprint' has no attribute 'Adafruit_Fingerprint'
已通过pip安装库,且Adafruit官方示例代码运行后也出现相同错误。测试代码如下:
import time import serial import adafruit_fingerprint # Open serial port uart = serial.Serial("/dev/ttyS0", baudrate=57600, timeout=1) # Initialize fingerprint sensor finger = adafruit_fingerprint.Adafruit_Fingerprint(uart) def get_fingerprint(): """Get a finger print image, template it, and see if it matches!""" print("Waiting for image...") while finger.get_image() != adafruit_fingerprint.OK: pass print("Templating...") if finger.image_2_tz(1) != adafruit_fingerprint.OK: return False print("Searching...") if finger.finger_search() != adafruit_fingerprint.OK: return False return True # Test the function while True: if get_fingerprint(): print("Fingerprint found!") else: print("Fingerprint not found.") time.sleep(1)
预期代码正常运行,寻求报错解决方法。
解决方法
这个错误的核心原因是:你安装的adafruit_fingerprint是CircuitPython适配版本,而当前使用的是标准Python环境,两者API结构不一致——CircuitPython版本库中没有Adafruit_Fingerprint类,对应的类是Fingerprint,错误码的引用方式也有区别。
方法1:修改代码适配CircuitPython版本库
调整代码的导入、初始化和错误码引用逻辑:
import time import serial from adafruit_fingerprint import Fingerprint, OK # Open serial port uart = serial.Serial("/dev/ttyS0", baudrate=57600, timeout=1) # Initialize fingerprint sensor finger = Fingerprint(uart) def get_fingerprint(): """Get a finger print image, template it, and see if it matches!""" print("Waiting for image...") while finger.get_image() != OK: pass print("Templating...") if finger.image_2_tz(1) != OK: return False print("Searching...") if finger.finger_search() != OK: return False return True # Test the function while True: if get_fingerprint(): print("Fingerprint found!") else: print("Fingerprint not found.") time.sleep(1)
方法2:安装标准Python适配的指纹库
如果你的环境是标准Python(非CircuitPython),可以安装专门适配的pyfingerprint库:
pip install pyfingerprint
安装完成后需要参考该库的官方文档调整代码结构,适配其API逻辑。
内容的提问来源于stack exchange,提问作者Soham Bhole
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