如何用Python结合CustomTkinter编写函数调整组件Grid布局位置？

需求说明 #

开发训练动作选择应用，需要实现一个函数：接收目标组件对象，将选中的训练动作组件（如self.bench_press）移至Grid布局的column=1，同时让column=2中所有位于该组件下方的其他组件上移一行。

现有代码片段 #

import tkinter as Tk
from PIL import Image

# 类内相关初始化代码
self.exframe = Tk.CTkFrame(master=self.tabview.tab("Workout Builder"), width=400, height=100, fg_color="#333333")
self.exframe.grid(row=0, column=0, rowspan=4, sticky="nsew")
self.exframe.grid_rowconfigure(4, weight=1)

self.scrollable_frame = Tk.CTkScrollableFrame(master=self.exframe, label_text="Your Exercises                               Choose Exercises", width=1000, height=500, fg_color="#333333")
self.scrollable_frame.grid(row=1, column=5, sticky="nsew")
self.scrollable_frame.grid_columnconfigure(0, weight=1)

self.bench_press_pic = Tk.CTkImage(light_image=Image.open("images/bench-press.png"), dark_image=Image.open("images/bench-press.png"), size=(175, 175))
self.bench_press = Tk.CTkButton(master=self.scrollable_frame, image=self.bench_press_pic, text="Barbell Bench Press", fg_color="#333333", text_color="white", font=Tk.CTkFont(size=26, weight="bold"), hover_color="#444444", corner_radius=38)
self.bench_press.grid(row=1, column=2)

尝试的报错函数 #

def addExercise(exercise):
    column, row = 1, 1
    exercise.grid(column=column, row=row)

问题分析与解决方案 #

原函数存在两个核心问题：

1. 未作为类方法实现，无法访问类内的scrollable_frame等对象，且直接固定row=1会导致组件重叠
2. 未处理column=2中组件的上移逻辑

以下是修正后的类方法实现：

def addExercise(self, exercise):
    # 获取目标组件当前的布局信息
    current_grid_info = exercise.grid_info()
    current_row = current_grid_info.get("row", 0)
    current_col = current_grid_info.get("column", 0)

    # 找到column=1的最后一行，将目标组件放在下一行（避免重叠）
    max_target_row = 0
    for child in self.scrollable_frame.winfo_children():
        child_grid = child.grid_info()
        if child_grid.get("column") == 1:
            child_row = child_grid.get("row", 0)
            if child_row > max_target_row:
                max_target_row = child_row
    target_row = max_target_row + 1
    exercise.grid(column=1, row=target_row, sticky="nsew")

    # 若原位置在column=2，将该行下方的所有组件上移一行
    if current_col == 2:
        for child in self.scrollable_frame.winfo_children():
            child_grid = child.grid_info()
            if child_grid.get("column") == 2 and child_grid.get("row", 0) > current_row:
                child.grid(row=child_grid["row"] - 1)

使用说明 #

给训练动作按钮绑定命令时，需通过lambda表达式传递组件自身作为参数：

self.bench_press.configure(command=lambda: self.addExercise(self.bench_press))

内容的提问来源于stack exchange，提问作者2185358