Python中如何移除时间列表中相邻近的时间记录并保存至CSV？

我是Python新手，现有如下格式的时间列表：

'2021-01-23 06:14:16'
'2021-01-23 06:14:17'
'2021-01-23 06:19:35'
'2021-01-23 07:05:03'
'2021-01-23 07:05:04'
'2021-01-23 07:05:33'
'2021-01-23 07:05:34'

我需要移除其中时间间隔极近的记录（如示例中相邻1秒的记录），最终得到如下结果并保存至CSV文件：

'2021-01-23 06:14:16'
'2021-01-23 06:19:35'
'2021-01-23 07:05:03'
'2021-01-23 07:05:33'

我尝试了以下代码，但无法正确运行，恳请帮忙解决：

data_detections = pd.read_csv('path/to/file.csv')
date_detec = data_detections.Fecha_UTC.values.tolist()
time_detec = data_detections.Hora_UTC.values.tolist()
com_date = data_detections.Fecha_UTC.values.tolist()
com_time = data_detections.Hora_UTC.values.tolist()

file_csv = open('path/to/file2.csv', "w")
file_csv.write('Fecha_UTC,Hora_UTC\n')

for t1,d1 in zip(time_detec,date_detec):
    h1 = "".join(t1[0:2])
    m1 = "".join(t1[3:5])
    s1 = "".join(t1[6:])
    tm_comp = d1+','+h1+':'+m1
    for t2,d2 in zip(com_time,com_date):
        h2 = "".join(t2[0:2])
        m2 = "".join(t2[3:5])
        s2 = "".join(t2[6:])
        dd = "".join(d2[8:])  
        mm = "".join(d2[5:7])
        yy = "".join(d2[0:4])
        time_UTC = d2+','+h2+':'+m2
        
        if tm_comp == time_UTC:
            if s1 == s2:
                pass
            elif int(s2)-10 < int(s1) < int(s2)+10:
                if s1 == s2:
                    print('Same')
            elif int(s1)-10 < int(s2) < int(s1)+10:
                if s1 != s2:
                    print(tm_comp+':'+str(s1))
                    file_csv.write(tm_comp+':'+str(s1)+'\n')
        else:
            continue

内容的提问来源于stack exchange，提问作者user25589007