如何合并列表中team键重复的复杂嵌套字典

我有一个字典列表，每个字典对应一个团队及其资产。同一团队可能对应多个字典，每个字典包含该团队的部分资产类型。需要将同一团队的字典合并，每个团队仅保留一个字典，整合其所有的资产类型。

原始数据 #

list_of_dicts = [
    {
        "team": "X",
        "description": "A description of X",
        "types": [
            {
                "type": "TYPEA",
                "assets": {
                    "high_value": [
                        {"id": "asset_1_id", "name": "asset_1_name"},
                        {"id": "asset_2_id", "name": "asset_2_name"},
                    ],
                    "low_value": [
                        {"id": "asset_3_id", "name": "asset_3_name"},
                        {"id": "asset_4_id", "name": "asset_4_name"},
                    ],
                },
            },
            {
                "type": "TYPEB",
                "assets": {
                    "high_value": [
                        {"id": "asset_1_id", "name": "asset_1_name"},
                        {"id": "asset_2_id", "name": "asset_2_name"},
                    ],
                    "low_value": [
                        {"id": "asset_3_id", "name": "asset_3_name"},
                        {"id": "asset_4_id", "name": "asset_4_name"},
                    ],
                },
            },
        ],
    },
    {
        "team": "X",
        "description": "A description of X",
        "types": [
            {
                "type": "TYPEC",
                "assets": {
                    "high_value": [
                        {"id": "asset_1_id", "name": "asset_1_name"},
                        {"id": "asset_2_id", "name": "asset_2_name"},
                    ],
                    "low_value": [
                        {"id": "asset_3_id", "name": "asset_3_name"},
                        {"id": "asset_4_id", "name": "asset_4_name"},
                    ],
                },
            }
        ],
    },
]

实现代码 #

merged_teams = {}
for team_item in list_of_dicts:
    team_name = team_item["team"]
    if team_name not in merged_teams:
        # 复制当前团队字典，避免修改原数据
        merged_teams[team_name] = team_item.copy()
        # 独立复制types列表，防止后续操作影响原数据
        merged_teams[team_name]["types"] = team_item["types"].copy()
    else:
        # 将当前团队的types追加到已合并的types列表中
        merged_teams[team_name]["types"].extend(team_item["types"])

# 转换为目标列表格式
result_list = list(merged_teams.values())

结果说明 #

执行上述代码后，result_list即为每个团队仅对应一个字典、整合所有资产类型的结果，示例输出如下：

[
    {
        "team": "X",
        "description": "A description of X",
        "types": [
            {"type": "TYPEA", "assets": {...}},
            {"type": "TYPEB", "assets": {...}},
            {"type": "TYPEC", "assets": {...}},
        ],
    }
]

内容的提问来源于stack exchange，提问作者James