如何限制DataGridView中同一机器数据不重复，仅特定条件允许单次重复？

• 常规规则：DataGridView中不允许同一机器的数据重复提交
• 例外规则：仅当问题类型为#Temperature Monitoring时，允许该机器的数据重复提交一次

![DataGridView]

while (read.Read())
{
    if (read["Selected_Problem"] != DBNull.Value && read["Selected_Problem"].ToString() == "#Temperature Monitoring")
    {
        submitToPending2();
        ScriptManager.RegisterClientScriptBlock(this, this.GetType(), "alertMessage", "alert('该机器已通知技术人员。')", true);

        if (read.HasRows)
        {
            ScriptManager.RegisterClientScriptBlock(this, this.GetType(), "alertMessage", "alert('该机器当前处于待处理或处理中状态，无法再次提交。')", true);
            clearTextBox();
        }
        else
        {
            submitToPending2();
            ScriptManager.RegisterClientScriptBlock(this, this.GetType(), "alertMessage", "alert('该机器已通知技术人员。')", true);
            //Response.Redirect("operatorView.aspx");
        }

        //read.Close();
        //con.Close();
    }
}
read.Close();
con.Close();
while (read.Read())
{
    if (read["Selected_Problem"] != DBNull.Value && read["Selected_Problem"].ToString() == "#Temperature Monitoring")
    {
        submitToPending2();
        ScriptManager.RegisterClientScriptBlock(this, this.GetType(), "alertMessage", "alert('该机器已通知技术人员。')", true);

        if (read.HasRows)
        {
            ScriptManager.RegisterClientScriptBlock(this, this.GetType(), "alertMessage", "alert('该机器当前处于待处理或处理中状态，无法再次提交。')", true);
            clearTextBox();
        }
        else
        {
            submitToPending2();
            ScriptManager.RegisterClientScriptBlock(this, this.GetType(), "alertMessage", "alert('该机器已通知技术人员。')", true);
            //Response.Redirect("operatorView.aspx");
        }

        //read.Close();
        //con.Close();
    }
}
read.Close();
con.Close();

内容的提问来源于stack exchange，提问作者IZZAT HATTA