Python中.zip文件解压函数失效问题排查求助

我编写了一个unzip_file函数，预期功能是接收一个ZIP文件路径，将其解压到原文件所在目录，代码如下：

def unzip_file(file_path):
    print(f"Unzipping file: {file_path}")
    if os.path.exists(file_path):
        if file_path[-4:] == ".zip":
            with zipfile.ZipFile(file_path, 'r') as zip_ref:
                try:
                    for file_name in zip_ref.namelist():
                        print(f"Found in zip: {file_name}")
                    print(os.path.dirname(file_path))
                    zip_ref.extractall(path=os.path.dirname(file_path))
                except Exception as e:
                    print(f"Error unzipping file: {e}")
            os.remove(file_path)
        else:
            print(f"File is not a zip file: {file_path}")
    else:
        print(f"File does not exist: {file_path}")

测试场景：ZIP文件名为zip_file.zip，路径为C:\example_folder\zip_file.zip，内部包含三个无文件夹的文本文件a.txt、b.txt、c.txt。运行时出现错误，报错信息如下：

Unzipping file: C:\example_folder\zip_file.zip
Found in zip: a.txt
Found in zip: b.txt
Found in zip: c.txt
C:\example_folder
Error unzipping file: [Errno 2]: No such file or directory- 'C:\\example_folder\\zip_file.zip\\a.txt'

请问extractall()为何无法正常工作？

问题解决 #

已排查出问题根源：文件路径过长。特此告知有类似问题的用户，确保文件路径长度不超过256字符即可解决该问题。

内容的提问来源于stack exchange，提问作者MSuccessor