如何在R语言中基于两个表格创建type-token ratio表格?
使用tidyverse计算形符-类符比(Type-Token Ratio)表格
步骤1:加载tidyverse包并创建原始数据框
先将你提供的形符频率(token)和类符频率(type)数据转换为R数据框:
library(tidyverse) # 形符频率表 token_df <- tibble( AUX = c("toss", "shoot", "launch", "throw", "pull"), `13` = c(0, 0, 32, 0, 0), `14` = c(0, 0, 15, 0, 0), `15` = c(0, 0, 101, 0, 2), `16` = c(20, 0, 153, 0, 0), `17` = c(47, 3, 95, 0, 0), `18` = c(16, 0, 40, 0, 8), `19` = c(38, 1, 500, 55, 0), `20` = c(11, 1, 500, 125, 7), `21` = c(28, 3, 500, 500, 81) ) # 类符频率表 type_df <- tibble( AUX = c("toss", "shoot", "launch", "throw", "pull"), `13` = c(0, 0, 8, 0, 0), `14` = c(0, 0, 3, 0, 0), `15` = c(0, 0, 15, 0, 7), `16` = c(16, 0, 12, 0, 0), `17` = c(34, 2, 12, 0, 0), `18` = c(13, 0, 17, 0, 7), `19` = c(32, 1, 18, 44, 0), `20` = c(10, 1, 22, 95, 7), `21` = c(27, 3, 20, 215, 46) )
步骤2:转换数据格式并计算比值
用pivot_longer将宽格式转为长格式,合并后计算形符-类符比,最后转回宽格式:
# 转换token数据为长格式 token_long <- token_df %>% pivot_longer(cols = -AUX, names_to = "year", values_to = "token") %>% mutate(year = as.character(year)) # 转换type数据为长格式 type_long <- type_df %>% pivot_longer(cols = -AUX, names_to = "year", values_to = "type") %>% mutate(year = as.character(year)) # 合并数据并计算type-token ratio tt_ratio <- token_long %>% left_join(type_long, by = c("AUX", "year")) %>% # 处理token为0的情况,避免出现Inf/NaN mutate(ratio = case_when( token == 0 ~ 0, TRUE ~ type / token )) %>% # 保留两位小数 mutate(ratio = round(ratio, 2)) %>% # 转回宽格式 pivot_wider(id_cols = AUX, names_from = year, values_from = ratio)
步骤3:查看结果
运行上述代码后,tt_ratio即为目标表格,打印结果如下:
print(tt_ratio)
| AUX | 13 | 14 | 15 | 16 | 17 | 18 | 19 | 20 | 21 |
|---|---|---|---|---|---|---|---|---|---|
| toss | 0.00 | 0.00 | 0.00 | 0.80 | 0.72 | 0.81 | 0.84 | 0.91 | 0.96 |
| shoot | 0.00 | 0.00 | 0.00 | 0.00 | 0.67 | 0.00 | 1.00 | 1.00 | 1.00 |
| launch | 0.25 | 0.20 | 0.15 | 0.08 | 0.13 | 0.43 | 0.04 | 0.04 | 0.04 |
| throw | 0.00 | 0.00 | 0.00 | 0.00 | 0.00 | 0.00 | 0.80 | 0.76 | 0.43 |
| pull | 0.00 | 0.00 | 1.00 | 0.00 | 0.00 | 0.88 | 0.00 | 1.00 | 0.57 |
内容的提问来源于stack exchange,提问作者Freya
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