Python游戏开发：无法在物品列表中匹配用户输入的问题

我正在开发一款文字冒险游戏，已成功实现场景移动功能，当前需完成拾取物品功能。当代码执行到if ask in myPlayer.location.items[item.name]:时出现错误，我查阅了字符串在列表中存在性的判断方法，但问题仍未解决。完整代码如下：

#MARK: Imports
import sys

#MARK: Classes
class Player(object):
    def __init__(self, name, location, job):
        self.name = name
        self.location = location
        self.job = job
        self.inventory = []
        self.gameOver = False

class Room(object):
    def __init__(self, name, description):
        self.name = name
        self.description = description
        self.exits = {}
        self.items = []

class Item(object):
    def __init__(self, name, description):
        self.name = name
        self.description = description

class Job(object):
    def __init__(self, name, health):
        self.name = name
        self.health = health

#MARK: Locations

yourHouse = Room("Your House", "This is your small house. Nothing has changed here")

townHall = Room("Town Hall", "This is the Town Hall. Sometimes people gather here to make decissions for the town")

townPark = Room("Town Park", "This is the towns small Park.\nThere is a small pond with a park bench on it's edge where you can sit and feed the ducks.\nA few trees provide shade.")

townGeneralStore = Room("The General Store", "The General Store is the largest building in town. Here you can buy almost everything you need.")

#MARK: Exits

yourHouse.exits = {'north': townHall, 'west': townPark}
townHall.exits = {'south': yourHouse, 'west': townGeneralStore}
townPark.exits = {'east': yourHouse, 'north': townGeneralStore}
townGeneralStore.exits = {'south': townPark, 'east': townHall}

#MARK: Jobs

fighter = Job("Fighter", 40)
sneak = Job("Sneak", 20)


#MARK: Create player

myPlayer = Player("", yourHouse, "")

#MARK: Create items
shovel = Item('Shovel', "You find a sturdy shovel. It looks like it could do some good bashing.")
stick = Item('Stick', 'You find a fragile looking stick, it looks like it could break easily.')

#MARK: Place Items
townHall.items.append(shovel)
townPark.items.append(stick)

print('\n' + myPlayer.location.name)
print(myPlayer.location.description)
room_exits = "\n" + "The exits are: \n"
for character in room_exits:
    sys.stdout.write(character)
    sys.stdout.flush()
for exit in myPlayer.location.exits:
    print(exit)
#MARK: Main game loop
while myPlayer.gameOver is False:
   # Start player in their house

    
    action = input('>')
    plaAction = action.lower()
    
    # Movement
    if plaAction in ['north', 'south', 'east', 'west']:
        if plaAction in myPlayer.location.exits:
            myPlayer.location = myPlayer.location.exits[action]
            print("\n" "You went to " + myPlayer.location.name + '.')
            print("\n" + myPlayer.location.description)
        for exit in myPlayer.location.exits:
            print(exit)
    
    # Pick up items
    if plaAction in ['get']:
        ask = input("What would you like to pick up?\n")
        print(type(ask))
        print(type(myPlayer.location.items))
        for item in myPlayer.location.items:
            if ask in myPlayer.location.items[item.name]:
                myPlayer.inventory.append(ask)
                print('You have picked up the ' + ask)
                print(myPlayer.inventory)
    
    # Exit Game command
    if plaAction == 'exit':
        myPlayer.gameOver = True

1. 索引使用错误：myPlayer.location.items是存储Item对象的列表，而非字典，不能用item.name作为索引访问列表元素，这是触发报错的直接原因。
2. 逻辑判断错误：判断用户输入物品是否存在的逻辑有误——应该对比用户输入的名称与物品对象的name属性，而非用in去判断一个不存在的列表元素。
3. 功能遗漏：拾取物品后未从房间物品列表中移除该物品，会导致玩家可重复拾取同一物品。

核心拾取功能修正 #

替换原代码中「Pick up items」部分的代码：

# Pick up items
if plaAction in ['get']:
    ask = input("What would you like to pick up?\n").lower()
    picked_success = False
    # 遍历房间内的物品对象
    for item in myPlayer.location.items:
        # 统一转小写，避免大小写不匹配问题
        if ask == item.name.lower():
            # 将物品对象加入背包，而非字符串
            myPlayer.inventory.append(item)
            # 从房间移除该物品
            myPlayer.location.items.remove(item)
            print(f'You have picked up the {item.name}')
            print(item.description)
            # 打印当前背包状态
            print("\nYour inventory:")
            for inv_item in myPlayer.inventory:
                print(f"- {inv_item.name}")
            picked_success = True
            break
    if not picked_success:
        print(f"There's no {ask} in this room!")

移动功能小修正 #

原移动代码中使用原始输入action作为字典键，可能因大小写不匹配报错，改为使用转小写后的plaAction：

# Movement
if plaAction in ['north', 'south', 'east', 'west']:
    if plaAction in myPlayer.location.exits:
        myPlayer.location = myPlayer.location.exits[plaAction]
        print(f"\nYou went to {myPlayer.location.name}.")
        print(f"\n{myPlayer.location.description}")
    # 打印当前房间出口
    print("\nExits:")
    for exit_dir in myPlayer.location.exits:
        print(f"- {exit_dir}")

• 初始化玩家时可以添加姓名输入、职业选择逻辑，让游戏更完整；
• 可以给Player类添加查看背包的方法，方便后续扩展；
• 物品描述可以在查看背包时显示，提升游戏体验。

内容的提问来源于stack exchange，提问作者Jake Carlile