如何用Groovy为地址字符串的数字添加空格（规避序数词异常）

需要将地址字符串中的数字逐个用空格分隔，兼容所有常见地址格式。例如：

"1234 South St City, NY 12345" → "1 2 3 4 South St City, NY 1 2 3 4 5"

• 尝试1：能实现数字分隔，但会错误处理"1st"这类带序数词的地址片段，给"1"和"st"之间添加空格，不符合需求

def address = "1234 South St City, NY 12345"
address = address.replaceAll(/(\d)/, '$1 ');
address = address.trim();
println(address);

• 尝试2-4：仅对长度3及以上的数字序列添加末尾空格，完全没实现逐个数字分隔的核心需求

// 尝试2
def address = "1234 South St City, NY 12345"
address = address.replaceAll(/\d{3,}/, '$0 ');
address = address.trim();
println(address);

// 尝试3
def address = "1234 South St City, NY 12345"
address = address.replaceAll(/(\d{3,})/, '$1 ');
address = address.trim();
println(address);

// 尝试4
def address = "1234 South St City, NY 12345"
address = address.replaceAll(/\d{3,5}/, '$0 ');
address = address.trim();
println(address);

使用带正向预查的正则表达式，仅对后面是数字或非字母字符的数字添加空格，避免破坏序数词格式：

def address = "123 1st St NW Hampton, IA 12345"
address = address.replaceAll(/(\d)(?=\d|[^a-zA-Z])/, '$1 ')
address = address.trim()
println(address)

正则逻辑说明 #

• (\d)：捕获单个数字
• (?=\d|[^a-zA-Z])：正向预查规则，确保当前数字的后续字符要么是另一个数字，要么是非字母字符（空格、逗号等），这样就不会匹配"1st"里的1（因为后面是字母s）

测试验证：

输入："123 1st St NW Hampton, IA 12345"
输出："1 2 3 1st St NW Hampton, IA 1 2 3 4 5"

完全满足需求，既分隔了纯数字序列的每个数字，又保留了地址中序数词的原有格式。

内容的提问来源于stack exchange，提问作者David