C#继承List类实现XML序列化时如何自定义元素节点名？

方法1：使用特性直接标记类 #

给继承List<string>的类添加[XmlElement]特性，直接指定自定义的元素节点名：

using System.Collections.Generic;
using System.Xml.Serialization;

[XmlElement("CustomItem")]
public class CustomStringList : List<string> { }

序列化示例代码：

var list = new CustomStringList { "Value1", "Value2" };
var serializer = new XmlSerializer(typeof(CustomStringList));
using var writer = new StringWriter();
serializer.Serialize(writer, list);
Console.WriteLine(writer.ToString());

输出XML结构：

<CustomStringList xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <CustomItem>Value1</CustomItem>
  <CustomItem>Value2</CustomItem>
</CustomStringList>

方法2：使用XmlAttributeOverrides动态指定（适合无法修改类源码的场景） #

如果不能修改继承List<string>的类的源码，可以通过XmlAttributeOverrides在创建序列化器时动态覆盖元素节点名：

using System.Collections.Generic;
using System.Xml.Serialization;

public class CustomStringList : List<string> { }

// 配置序列化规则
var attributeOverrides = new XmlAttributeOverrides();
var xmlAttributes = new XmlAttributes();
xmlAttributes.XmlElements.Add(new XmlElementAttribute("CustomItem"));
attributeOverrides.Add(typeof(CustomStringList), xmlAttributes);

// 创建自定义序列化器并执行序列化
var serializer = new XmlSerializer(typeof(CustomStringList), attributeOverrides);
var list = new CustomStringList { "Value1", "Value2" };
using var writer = new StringWriter();
serializer.Serialize(writer, list);
Console.WriteLine(writer.ToString());

输出结果与方法1完全一致，元素节点名为<CustomItem>。

以上两种方法均无需实现IXmlSerializable接口，可直接实现案例C编码方式下得到案例B序列化结果的需求。

内容的提问来源于stack exchange，提问作者PapaAtHome