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获取各表中code为access的最新Timestamp的SQL查询请求

需求说明

获取每个Table中Code为'access'的最新Timestamp,查询无需考虑Status字段。

原始数据表

TableStatusCodeTimestamp
BudgetSuccessaccess03-02-2024T08:04:23.19Z
PropertyFailedaccess03-02-2024T08:04:23.19Z
TransferSuccessaccess03-02-2024T08:04:23.19Z
PropertySuccessaccess03-02-2024T08:04:23.19Z
LoadSuccessaccess03-02-2024T00:07:02.54Z
PropertyFailedaccess03-02-2024T00:07:02.54Z
TransferSuccessuprow03-02-2024T00:07:02.54Z
LoadSuccessuprow01-02-2024T18:17:54.42Z
PropertyFaileduprow01-02-2024T18:17:54.42Z
TransferSuccessuprow01-02-2024T18:17:54.42Z

SQL查询语句

使用窗口函数按Table分组,取每组内Timestamp最新的记录,同时过滤Code为'access'的数据:

WITH ranked_records AS (
    SELECT 
        *,
        ROW_NUMBER() OVER (PARTITION BY "Table" ORDER BY "Timestamp" DESC) AS row_num
    FROM your_table_name
    WHERE Code = 'access'
)
SELECT "Table", Status, Code, "Timestamp"
FROM ranked_records
WHERE row_num = 1;

注意:将your_table_name替换为实际表名;若Timestamp为字符串类型,需确保数据库能正确识别其时间顺序,必要时可先转换为时间类型再排序。

预期查询结果

TableStatusCodeTimestamp
BudgetSuccessaccess03-02-2024T08:04:23.19Z
PropertyFailedaccess03-02-2024T08:04:23.19Z
TransferSuccessaccess03-02-2024T08:04:23.19Z
LoadSuccessaccess03-02-2024T00:07:02.54Z

内容的提问来源于stack exchange,提问作者Pranjal

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最近更新时间:2026.06.17 18:53:16