如何按周分组展示全年日期（不使用PHP DateTime）

你可以直接修改原代码的数组存储逻辑，用二维数组按周分组日期，最后遍历分组数据生成表格。以下是调整后的完整代码：

<?php
$now = mktime(0,0,0,1,1,2024);
// 用strtotime计算一年后更准确，避免闰年误差
$aYearLater = strtotime('+1 year', $now);
$weekGroups = []; // 按周分组的数组

$friday = strtotime('Next Friday', strtotime('-1 Day', $now));
$saturday = strtotime('Next Saturday', strtotime('-1 Day', $now));
$sunday = strtotime('Next Sunday', strtotime('-1 Day', $now));
$monday = strtotime('Next Monday', strtotime('-1 Day', $now));
$tuesday = strtotime('Next Tuesday', strtotime('-1 Day', $now));
$wednesday = strtotime('Next Wednesday', strtotime('-1 Day', $now));
$thursday = strtotime('Next Thursday', strtotime('-1 Day', $now));

while(true){
    $currentWeek = []; // 存储当前周的日期
    
    // 处理周六
    if($saturday <= $aYearLater){
        $currentWeek[] = [
            'date' => date('Y-m-d l', $saturday),
            'daynum' => date('w', $saturday)
        ];
    }
    // 处理周日
    if($sunday <= $aYearLater){
        $currentWeek[] = [
            'date' => date('Y-m-d l', $sunday),
            'daynum' => date('w', $sunday)
        ];
    }
    // 处理周一到周五
    if($monday <= $aYearLater) $currentWeek[] = ['date' => date('Y-m-d l', $monday), 'daynum' => date('w', $monday)];
    if($tuesday <= $aYearLater) $currentWeek[] = ['date' => date('Y-m-d l', $tuesday), 'daynum' => date('w', $tuesday)];
    if($wednesday <= $aYearLater) $currentWeek[] = ['date' => date('Y-m-d l', $wednesday), 'daynum' => date('w', $wednesday)];
    if($thursday <= $aYearLater) $currentWeek[] = ['date' => date('Y-m-d l', $thursday), 'daynum' => date('w', $thursday)];
    if($friday <= $aYearLater) $currentWeek[] = ['date' => date('Y-m-d l', $friday), 'daynum' => date('w', $friday)];
    
    // 如果当前周有数据，加入分组数组
    if(!empty($currentWeek)){
        $weekGroups[] = $currentWeek;
    }
    
    // 所有日期都超过一年后，终止循环
    if($friday > $aYearLater){
        break;
    }
    
    // 日期往后推一周
    $friday = strtotime('+1 Week', $friday);
    $saturday = strtotime('+1 Week', $saturday);
    $sunday = strtotime('+1 Week', $sunday);
    $monday = strtotime('+1 Week', $monday);
    $tuesday = strtotime('+1 Week', $tuesday);
    $wednesday = strtotime('+1 Week', $wednesday);
    $thursday = strtotime('+1 Week', $thursday);
}

// 生成表格输出
echo '<table border="1">';
// 表头：周六到周五
echo '<tr><th>周六</th><th>周日</th><th>周一</th><th>周二</th><th>周三</th><th>周四</th><th>周五</th></tr>';
foreach($weekGroups as $week){
    echo '<tr>';
    foreach($week as $day){
        echo '<td>'.$day['date'].'<br>'.$day['daynum'].'</td>';
    }
    // 如果最后一周天数不足7天，补空单元格
    $missingDays = 7 - count($week);
    for($i=0; $i<$missingDays; $i++){
        echo '<td></td>';
    }
    echo '</tr>';
}
echo '</table>';
?>

关键调整说明 #

• 将原一维数组改为$weekGroups二维数组，每个子数组对应一周的所有日期
• 每次循环一周时，用$currentWeek临时数组收集当前周的日期，完成后再加入分组数组
• 修正一年后日期的计算方式，用strtotime('+1 year', $now)替代固定秒数，避免闰年（2024是闰年）导致的误差
• 最后遍历分组数组生成HTML表格，每行对应一周，表头匹配你原代码的日期顺序，最后一周天数不足时自动补空单元格

内容的提问来源于stack exchange，提问作者R13