Gradle Kotlin-DSL中如何正确设置apiVersion与languageVersion？

我在Gradle文件中使用如下声明：

plugins {
    `kotlin-dsl`
}

kotlin {
    compilerOptions {
        apiVersion.set("2.1")
        languageVersion.set("2.1")
    }
}

编译时出现如下错误：

* Where:
Build file '/home/peng/git/spookystuff/prover-commons/buildSrc/build.gradle.kts' line: 9

* What went wrong:
Script compilation errors:

  Line 09:         apiVersion.set("2.1")
                              ^ None of the following functions can be called with the arguments supplied: 
                                  public abstract fun set(provider: Provider<out KotlinVersion!>!): Unit defined in org.gradle.api.provider.Property
                                  public abstract fun set(value: KotlinVersion?): Unit defined in org.gradle.api.provider.Property

  Line 10:         languageVersion.set("2.1")
                                   ^ None of the following functions can be called with the arguments supplied: 
                                       public abstract fun set(provider: Provider<out KotlinVersion!>!): Unit defined in org.gradle.api.provider.Property
                                       public abstract fun set(value: KotlinVersion?): Unit defined in org.gradle.api.provider.Property

2 errors

由于KotlinVersion类未直接对我暴露，请问应如何正确设置这两个参数？

你可以通过以下两种方式正确设置apiVersion和languageVersion：

方法1：使用全限定名调用KotlinVersion.valueOf #

直接通过全限定类名获取KotlinVersion实例，无需额外导入：

plugins {
    `kotlin-dsl`
}

kotlin {
    compilerOptions {
        apiVersion.set(org.jetbrains.kotlin.gradle.dsl.KotlinVersion.valueOf("2.1"))
        languageVersion.set(org.jetbrains.kotlin.gradle.dsl.KotlinVersion.valueOf("2.1"))
    }
}

方法2：导入KotlinVersion类后使用 #

先导入对应的KotlinVersion类，再调用valueOf方法：

import org.jetbrains.kotlin.gradle.dsl.KotlinVersion

plugins {
    `kotlin-dsl`
}

kotlin {
    compilerOptions {
        apiVersion.set(KotlinVersion.valueOf("2.1"))
        languageVersion.set(KotlinVersion.valueOf("2.1"))
    }
}

这两种方式都能生成符合要求的KotlinVersion实例，解决编译报错问题。

内容的提问来源于stack exchange，提问作者tribbloid