如何使用PowerShell定位XML元素并添加带属性的子元素

需要给XML中Key属性为ToolSetManager的<Record>元素追加3个带<Path>和<Title>子节点的<ToolSet>节点。以下是正确实现方案：

原XML结构 #

<?xml version="1.0" encoding="utf-8"?>
<UserPreferences Version="3">
  <Record Key="ProfileManager">
    <Path>C:\Users\bob\AppData\Roaming\Software\21\</Path>
  </Record>
  <Record Key="Measurement Creation Context">
    <SnapOrthogonal>False</SnapOrthogonal>
    <SnapContent>True</SnapContent>
   </Record>
  <Record Key="WebFavoritesList" />
  <Record Key="DefaultsManager" />
  <Record Key="ToolSetManager">
    <ToolSet>
      <Path>Tool Set 1.btx</Path>
      <Title>Tool Set 1</Title>
    </ToolSet>
    <ToolSet>
      <Path>My Tool Set.btx</Path>
      <Title>My Tool Set</Title>
    </ToolSet>
  </Record>
  <Record Key="RecentFileList" />
  <Record Key="TemplateData" />

     .
   </Record>
</UserPreferences>

用户原错误代码 #

$xml = [xml](Get-Content "$env:appdata\software\21\UserPreferences.xml")

#Loop to find the Element with the Key "ToolSetManager"
#Hopefully there is a simpler/direct way to get here?
$allRecordKeys = $xml.UserPreferences.Record.key

foreach ($Key in $allRecordKeys) {
 if ($Key -eq "ToolSetManager") {

   $newElement1 = $xml.CreateElement("ToolSet")
   $newElement1.SetAttribute("Path", "Null.btx")
   $newElement1.SetAttribute("Title", "Null")

# This is where I can't figure out what should go before the .appendChild...:
   $xml.RevuUserPreferences.Record.ToolSetManager.AppendChild($newElement1)

   $xml.save("$env:appdata\software\21\UserPreferences.xml")
   }
 }

正确实现步骤 #

1. 快速定位目标节点 #

不用循环遍历，直接用两种方式快速定位Key="ToolSetManager"的<Record>节点：

# 方式1：XPath直接查询（最快捷）
$targetRecord = $xml.SelectSingleNode("//Record[@Key='ToolSetManager']")

# 方式2：PowerShell属性筛选
$targetRecord = $xml.UserPreferences.Record | Where-Object { $_.Key -eq "ToolSetManager" }

2. 批量创建并追加子元素 #

注意：原XML中<Path>和<Title>是<ToolSet>的子节点，不是属性，需修正创建逻辑：

# 定义要添加的3组ToolSet数据
$newToolSets = @(
    @{ Path = "New Tool Set 1.btx"; Title = "New Tool Set 1" },
    @{ Path = "New Tool Set 2.btx"; Title = "New Tool Set 2" },
    @{ Path = "New Tool Set 3.btx"; Title = "New Tool Set 3" }
)

foreach ($ts in $newToolSets) {
    # 创建ToolSet父节点
    $toolSetNode = $xml.CreateElement("ToolSet")
    
    # 创建Path子节点并赋值
    $pathNode = $xml.CreateElement("Path")
    $pathNode.InnerText = $ts.Path
    $toolSetNode.AppendChild($pathNode) | Out-Null
    
    # 创建Title子节点并赋值
    $titleNode = $xml.CreateElement("Title")
    $titleNode.InnerText = $ts.Title
    $toolSetNode.AppendChild($titleNode) | Out-Null
    
    # 将ToolSet节点追加到目标Record下
    $targetRecord.AppendChild($toolSetNode) | Out-Null
}

3. 保存修改后的XML #

$xml.Save("$env:appdata\software\21\UserPreferences.xml")

完整正确代码 #

# 加载XML文件
$xmlPath = "$env:appdata\software\21\UserPreferences.xml"
$xml = [xml](Get-Content $xmlPath)

# 定位目标Record节点
$targetRecord = $xml.SelectSingleNode("//Record[@Key='ToolSetManager']")

# 定义要添加的3组ToolSet数据
$newToolSets = @(
    @{ Path = "New Tool Set 1.btx"; Title = "New Tool Set 1" },
    @{ Path = "New Tool Set 2.btx"; Title = "New Tool Set 2" },
    @{ Path = "New Tool Set 3.btx"; Title = "New Tool Set 3" }
)

# 批量创建并追加子元素
foreach ($ts in $newToolSets) {
    $toolSetNode = $xml.CreateElement("ToolSet")
    
    $pathNode = $xml.CreateElement("Path")
    $pathNode.InnerText = $ts.Path
    $toolSetNode.AppendChild($pathNode) | Out-Null
    
    $titleNode = $xml.CreateElement("Title")
    $titleNode.InnerText = $ts.Title
    $toolSetNode.AppendChild($titleNode) | Out-Null
    
    $targetRecord.AppendChild($toolSetNode) | Out-Null
}

# 保存修改
$xml.Save($xmlPath)

关键修正说明 #

• 原代码错误将<Path>和<Title>当成属性处理，实际是子节点，需用CreateElement创建并设置InnerText。
• 用XPath或Where-Object直接筛选目标节点，避免无效遍历，逻辑更简洁可靠。
• 修正了原代码中错误的节点引用$xml.RevuUserPreferences，对应XML根节点UserPreferences。

内容的提问来源于stack exchange，提问作者ITSteve