如何从文件部署应用设置至Azure标准逻辑应用？

问题 #

我正尝试将应用设置部署至Azure标准逻辑应用，希望从文件读取应用设置而非直接写入YAML文件。目前使用Azure Logic Apps DevOps任务部署工作流等内容，其他环节均正常，但应用设置从文件读取部署的需求无法实现。

曾尝试读取存储应用设置的JSON文件传递给部署任务但未成功；也尝试用az logicapp config appsettings set命令以文件作为输入，但该命令文档未提及文件输入（az functionapp config appsettings支持@filename格式，但仅适用于Function App）。

当前模板YAML配置了两种部署方式：

1. 通过AzureLogicAppsStandardRelease任务，此方式可正常工作但需在主YAML中声明应用设置字符串；
2. 最后一步用Azure CLI尝试读取文件部署，但未生效。

当前模板YAML代码如下：

parameters:
- name: logicAppName
  type: string
- name: parametersSubFolder
  type: string
- name: resourceGroupName
  type: string
- name: appSettings
  type: object
  default: []


jobs:
- job: logic_app_build
  displayName: 'Build and publish logic app'

  - task: AzureLogicAppsStandardBuild@0
    displayName: 'Azure Logic Apps Standard Build'
    inputs:
      sourceFolder: '$(Build.SourcesDirectory)'
      deploymentFolder: '$(System.DefaultWorkingDirectory)/deployment/'
      deploymentWorkflowParametersFile: '$(System.DefaultWorkingDirectory)/deployment/workflowparameters/${{ parameters.parametersSubFolder }}/parameters.json'
      archiveFile: '$(Build.ArtifactStagingDirectory)/$(Build.BuildId).zip'

  #deployar zip-filen
  - task: AzureLogicAppsStandardRelease@0
    displayName: 'Azure Logic Apps Standard Release'
    inputs:
        connectedServiceName: "serviceConnection"
        appName : '${{ parameters.resourceGroupName }}-${{ parameters.logicAppName }}'
        resourceGroupName: '${{ parameters.resourceGroupName }}'
        appSettings: |
          ${{ convertToJson(parameters.appSettings) }}
        package: '$(Build.ArtifactStagingDirectory)/$(Build.BuildId).zip'

  - task: AzureCLI@2
    inputs:
      azureSubscription:  "sc-sp-pi-${{ parameters.resourceGroupName }}-logicapps-deployment"
      scriptType: 'pscore'
      scriptLocation: 'inlineScript'
      inlineScript: |
        /usr/bin/az logicapp config appsettings set --resource-group ${{ parameters.resourceGroupName }} --name ${{ parameters.resourceGroupName }}-${{ parameters.logicAppName }} --settings "@$(System.DefaultWorkingDirectory)/deployment/workflowparameters/${{ parameters.parametersSubFolder }}/AppSettings.txt"

请问有什么可行的实现方法？是否只能将应用设置直接写入YAML文件？

可行方案 #

方案1：通过PowerShell读取JSON文件并传递给部署任务 #

先新增PowerShell任务读取JSON格式的应用设置文件，将内容转为JSON字符串存入变量，再在AzureLogicAppsStandardRelease任务中引用该变量：

1. 添加读取文件的PowerShell任务：

- task: PowerShell@2
  displayName: 'Load App Settings from JSON'
  inputs:
    targetType: 'inline'
    script: |
      $appSettingsContent = Get-Content -Path "$(System.DefaultWorkingDirectory)/deployment/workflowparameters/${{ parameters.parametersSubFolder }}/appsettings.json" -Raw
      Write-Host "##vso[task.setvariable variable=AppSettingsJson;]$appSettingsContent"

2. 修改AzureLogicAppsStandardRelease任务的appSettings输入：

- task: AzureLogicAppsStandardRelease@0
  displayName: 'Azure Logic Apps Standard Release'
  inputs:
      connectedServiceName: "serviceConnection"
      appName : '${{ parameters.resourceGroupName }}-${{ parameters.logicAppName }}'
      resourceGroupName: '${{ parameters.resourceGroupName }}'
      appSettings: $(AppSettingsJson)
      package: '$(Build.ArtifactStagingDirectory)/$(Build.BuildId).zip'

方案2：改进Azure CLI命令，手动解析文件内容 #

由于az logicapp config appsettings set不支持@filename格式，可以通过脚本读取文件内容，将其转为命令可接受的参数格式后传递：

若文件为键值对格式（每行KEY=VALUE）：

- task: AzureCLI@2
  inputs:
    azureSubscription:  "sc-sp-pi-${{ parameters.resourceGroupName }}-logicapps-deployment"
    scriptType: 'pscore'
    scriptLocation: 'inlineScript'
    inlineScript: |
      $settingsLines = Get-Content -Path "$(System.DefaultWorkingDirectory)/deployment/workflowparameters/${{ parameters.parametersSubFolder }}/AppSettings.txt"
      $settingsArgs = $settingsLines | ForEach-Object { "--settings $_" }
      az logicapp config appsettings set --resource-group ${{ parameters.resourceGroupName }} --name ${{ parameters.resourceGroupName }}-${{ parameters.logicAppName }} $settingsArgs

若文件为JSON格式：

- task: AzureCLI@2
  inputs:
    azureSubscription:  "sc-sp-pi-${{ parameters.resourceGroupName }}-logicapps-deployment"
    scriptType: 'pscore'
    scriptLocation: 'inlineScript'
    inlineScript: |
      $appSettings = Get-Content -Path "$(System.DefaultWorkingDirectory)/deployment/workflowparameters/${{ parameters.parametersSubFolder }}/appsettings.json" -Raw | ConvertFrom-Json
      $settingsArgs = @()
      foreach ($key in $appSettings.PSObject.Properties.Name) {
          $settingsArgs += "--settings $key=$($appSettings.$key)"
      }
      az logicapp config appsettings set --resource-group ${{ parameters.resourceGroupName }} --name ${{ parameters.resourceGroupName }}-${{ parameters.logicAppName }} $settingsArgs

方案3：使用ARM模板部署应用设置 #

创建ARM模板定义应用设置资源，再通过模板部署任务读取参数文件完成部署：

1. 编写ARM模板文件（比如appsettings-template.json）：

{
  "$schema": "https://schema.management.azure.com/schemas/2019-04-01/deploymentTemplate.json#",
  "contentVersion": "1.0.0.0",
  "parameters": {
    "logicAppName": {
      "type": "string"
    },
    "appSettings": {
      "type": "object"
    }
  },
  "resources": [
    {
      "type": "Microsoft.Web/sites/config",
      "name": "[concat(parameters('logicAppName'), '/appsettings')]",
      "apiVersion": "2022-03-01",
      "properties": "[parameters('appSettings')]"
    }
  ]
}

2. 添加ARM模板部署任务：

- task: AzureResourceManagerTemplateDeployment@3
  displayName: 'Deploy App Settings via ARM'
  inputs:
    deploymentScope: 'Resource Group'
    azureResourceManagerConnection: "serviceConnection"
    resourceGroupName: '${{ parameters.resourceGroupName }}'
    templateLocation: 'Linked artifact'
    csmFile: '$(System.DefaultWorkingDirectory)/appsettings-template.json'
    csmParametersFile: '$(System.DefaultWorkingDirectory)/deployment/workflowparameters/${{ parameters.parametersSubFolder }}/appsettings-params.json'
    deploymentMode: 'Incremental'

内容的提问来源于stack exchange，提问作者Emma Gustafsson