PowerShell 5.1如何原样打印含特殊符号的JSON数组值？

问题背景 #

环境：PowerShell 5.1
目标JSON片段：

"MyAddresses": ["email100@my.com", "email200@my.com", "email300@my.com", "email400@my.com"],

现有脚本可获取该键对应的值，但输出时丢失了括号、双引号和逗号，无法保留原始JSON格式。

问题原因 #

现有脚本使用ConvertFrom-Json将JSON内容转换为PowerShell对象，数组类型的属性在直接拼接字符串输出时，会被PowerShell自动展开为空格分隔的纯文本，导致原始JSON格式丢失。

解决方案 #

方案一：将数组转回JSON格式 #

修改脚本中提取并输出值的部分，用ConvertTo-Json把PowerShell数组重新转换成JSON字符串，配合-Compress参数可以输出紧凑的单行格式：

修改后的完整脚本：

# Define the path to the JSON file on the remote computers
$jsonFilePath = "C:\mydata.json"

# Script block to run on each remote computer
$scriptBlock = {
    param ($jsonFilePath)
    
    try {
        # Read the JSON file content
        $jsonContent = Get-Content -Path $jsonFilePath -Raw | ConvertFrom-Json

        # 将提取的数组转回JSON格式
        $receiverAddress = $jsonContent.Notification.ReceiverAddresses | ConvertTo-Json -Compress

        # Output the value
        Write-Output "******************************** $($env:COMPUTERNAME) - START OF DATA ********************************************"
        Write-Output "ReceiverAddress: $receiverAddress"
        Write-Output "******************************* $($env:COMPUTERNAME) - END OF DATA *********************************************"
    }
    catch {
        Write-Output "Error on $($env:COMPUTERNAME): $_"
    }
}

# Define the list of remote computers
$computers = 
@"
server1
server2
"@ -split [Environment]::NewLine

# Run the script block on each remote computer in parallel
$jobs = Invoke-Command -ComputerName $computers -ScriptBlock $scriptBlock -ArgumentList $jsonFilePath -AsJob

# Wait for all jobs to complete
$jobs | ForEach-Object { $_ | Wait-Job }

# Retrieve and display the results
$jobs | ForEach-Object {
    try {
        $result = Receive-Job -Job $_
        Write-Output $result
    }
    catch {
        Write-Output "Failed to retrieve job results for $($_.Location): $_"
    }
    finally {
        Remove-Job -Job $_
    }
}

方案二：直接提取JSON片段（不转换对象） #

如果不需要处理JSON中的其他内容，也可以用正则表达式直接从原始JSON字符串中提取目标键的数组部分，避免对象转换的步骤：

修改后的脚本块关键部分：

try {
    # 读取原始JSON字符串
    $jsonRawContent = Get-Content -Path $jsonFilePath -Raw

    # 用正则匹配提取ReceiverAddresses的数组内容
    if ($jsonRawContent -match '"ReceiverAddresses":\s*(\[.*?\])') {
        $receiverAddress = $matches[1]
    } else {
        $receiverAddress = "未找到ReceiverAddresses键"
    }

    # Output the value
    Write-Output "******************************** $($env:COMPUTERNAME) - START OF DATA ********************************************"
    Write-Output "ReceiverAddress: $receiverAddress"
    Write-Output "******************************* $($env:COMPUTERNAME) - END OF DATA *********************************************"
}
catch {
    Write-Output "Error on $($env:COMPUTERNAME): $_"
}

内容的提问来源于stack exchange，提问作者Rod