如何修改C#中事件自动生成的参数默认名称?
如何自定义C#事件处理方法的默认参数名?
我在创建C#事件时,不想使用默认生成的arg1、arg2这类参数名称,希望事件处理方法能从TypeName_MethodName(int arg1, string arg2)变为TypeName_MethodName(int age, string name),请问该怎么设置自定义的默认参数名?
补充示例代码(代码效率问题无需关注)
namespace Test { public static class People { public static event Action<int, string> OnPersonAdded = (age, name) => { }; public static void AddPerson(int age, string name) { if (!PeopleByAge.TryAdd(age, [name])) { PeopleByAge[age].Add(name); } OnPersonAdded(age, name); } public static Dictionary<int, List<string>> PeopleByAge = []; } public static class Program { public static void Main(string[] args) { People.OnPersonAdded += People_OnPersonAdded; People.AddPerson(int.Parse(args[0]), args[1]); } private static void People_OnPersonAdded(int arg1, string arg2) { Console.WriteLine($"Add person {arg2}, aged {arg1}."); } } }
解决方案
核心问题在于Action<int, string>这类泛型委托的参数没有显式命名,IDE只能用arg1、arg2这类默认名称生成处理方法。要解决这个问题,最直接的方式是自定义带明确参数名的委托类型:
1. 定义自定义委托
在合适的命名空间下,创建一个委托类型,明确指定参数的名称:
public delegate void PersonAddedHandler(int age, string name);
2. 修改事件的类型
将原来的Action<int, string>替换为自定义的委托类型:
public static event PersonAddedHandler OnPersonAdded = (age, name) => { };
3. 自动生成事件处理方法
此时再通过IDE的自动补全(比如在People.OnPersonAdded +=后按Tab键),生成的事件处理方法就会自动使用自定义的参数名:
private static void People_OnPersonAdded(int age, string name) { Console.WriteLine($"Add person {name}, aged {age}."); }
修改后的完整代码
namespace Test { // 自定义委托类型,明确参数名称 public delegate void PersonAddedHandler(int age, string name); public static class People { public static event PersonAddedHandler OnPersonAdded = (age, name) => { }; public static void AddPerson(int age, string name) { if (!PeopleByAge.TryAdd(age, [name])) { PeopleByAge[age].Add(name); } OnPersonAdded(age, name); } public static Dictionary<int, List<string>> PeopleByAge = []; } public static class Program { public static void Main(string[] args) { People.OnPersonAdded += People_OnPersonAdded; People.AddPerson(int.Parse(args[0]), args[1]); } // 参数名自动变为age和name private static void People_OnPersonAdded(int age, string name) { Console.WriteLine($"Add person {name}, aged {age}."); } } }
内容的提问来源于stack exchange,提问作者Lerpmcgerk
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