Telethon send_gift函数跨脚本调用报错：Cannot send requests while disconnected

问题原因 #

1. client.start()是异步函数，原代码未使用await，导致客户端还未完成连接就执行后续请求
2. 调用client(functions.xxxRequest())时未加await，这些请求方法都是异步的，必须等待执行完成
3. 缺少客户端关闭逻辑，可能引发资源占用问题

修改后的完整代码 #

relayer.py
import asyncio
from telethon import TelegramClient, functions
from telethon.tl.types import InputInvoiceStarGift
import config

async def send_gift(username, gift_id=config.teddy_id):
    client = TelegramClient(session_name, api_id, api_hash)
    try:
        # 等待客户端完成连接初始化
        await client.start(phone=config.phone, password=config.two_factor)
        
        receiver_peer = await client.get_input_entity(username)
        print(receiver_peer)

        invoice = InputInvoiceStarGift(
            peer=receiver_peer,
            gift_id=gift_id
        )

        print(f"Generated Invoice: {invoice}")

        # 异步调用支付表单请求，添加await
        payment_form = await client(functions.payments.GetPaymentFormRequest(invoice=invoice))

        if payment_form:
            print("Payment form retrieved successfully!")

            # 异步调用发送礼物请求，添加await
            payment_result = await client(functions.payments.SendStarsFormRequest(
                form_id=payment_form.form_id,
                invoice=invoice
            ))

            print(f"Payment successful: {payment_result.stringify()}")
    except Exception as e:
        print(f"An error occurred: {e}")
    finally:
        # 确保客户端最终关闭，释放资源
        await client.disconnect()

关键修改点 #

• 在client.start()前添加await，等待客户端完成连接流程
• 所有client(functions.xxxRequest())调用前添加await，保证异步请求执行完成
• 添加finally块，无论是否发生异常，都强制关闭客户端，避免资源泄漏

内容的提问来源于stack exchange，提问作者Артем Куулар